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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 654609Generated: October 30, 2026

Phenylacetylene → Benzene, iodoethynyl-

https://huagongshe.com/reaction/654609

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPhenylacetyleneHCID 10821—
Reactant1,1,1,2,2,3,3,4,4,5,5,6,6-Tridecafluoro-6-iodohexaneHCID 67733—
ReactantTetrabutylammonium Fluoride TrihydrateHCID 11726816—
ProductBenzene, iodoethynyl-HCID 9938255.3%

Reaction Steps

In a 10 mL round-bottom flask, 1.02 g of phenylacetylene (10 mmol), 4.46 g of perfluoro-n-hexyl iodide (10 mmol), and 300 mg of tetra-n-butylammonium fluoride trihydrate (0.948 mmol) were mixed at 24° C. for 1 h. Gas chromatographic analysis of the resulting mixture showed that it contained 1.26 g of 1-iodo-2phenylacetylene (55% yield) and 0.45 g of unconverted phenylacetylene.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05132475
Source datasetuspto-grants-1992_07
ORD IDord-4dd0112ef71b4798bf8259f7c69f333c
Source noteuspto-grants-1992_07