Sodium Hydroxide → 4-Methoxyphenylacetic Acid
Reaction equation
[CH3:1][O:2][C:3]1[CH:8]=[CH:7][C:6]([CH2:9][C:10]([O:12]CC)=[O:11])=[CH:5][CH:4]=1.[OH-].[Na+]>CO.O>[CH3:1][O:2][C:3]1[CH:4]=[CH:5][C:6]([CH2:9][C:10]([OH:12])=[O:11])=[CH:7][CH:8]=1Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
To a solution of ethyl 2-(4-methoxyphenyl)acetate (12 g, 0.06 mol) in MeOH (150 mL) was added dropwise a solution of NaOH (9.8 g, 0.24 mol) in water (50 mL). The mixture was then stirred at RT for 1 h and concentrated in vacuo, the residue was acidified with HCl (1N) and extracted with EtOAc (2×400 mL). The combined organic layers were washed with water, dried over Na2SO4 and concentrated in vacuo to afford 2-(4-methoxyphenyl)acetic acid (10 g, 67%) as a yellow oil.
Workup
- concentrationconcentrated in vacuo
- extractionextracted with EtOAc (2×400 mL)
- washThe combined organic layers were washed with water
- dry with materialdried over Na2SO4
- concentrationconcentrated in vacuo
Sources & evidence
- ORD record
- ord-a7fb9f814d6241efa727741a8d541bc9
- Source dataset
- uspto-grants-2011_12
- Patent number
- US08071595B2
Reaction notes
Loading…