HRID65708

反应详情

EQUATION

反应方程式

HRID 65708 的结构方程式

PROCEDURE

实验过程

By substituting 3-piperazinopropyl chloride for the 1-chloro-2-morpholinoethane in the procedure of Example 5 and utilizing the 2-methyl-4H-pyrazolo[1,5-a]pyrazolo-[4',3':5,6]pyrido[3,4-e]pyrimidin-5(8H)-one product of Example 8, 2-methyl-4-(3-piperazino)propyl-4H-pyrazolo[1,5-a]-pyrazolo[4',3':5,6]pyrido[3,4-e]pyrimidin-5(8H)-one is obtained.