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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 6577Generated: October 26, 2026

Iodoethane → N-Ethylphenothiazine

https://huagongshe.com/reaction/6577

Reaction equation

Participants

RoleNameHCIDCharge
ReactantIodoethaneHCID 6340—
ReactantPhenothiazineHCID 7108—
ReactantPotassium HydroxideHCID 14797—
CatalystTetrabutylammonium hydrogen sulfateHCID 94433—
SolventTolueneHCID 1140—
ProductN-EthylphenothiazineHCID 219178—

Reaction Steps

A mixture of 10 g (0.05 mol) of phenothiazine, 11.7 g (0.075 mol) of iodoethane, 4.2 g (0.075 mol) of potassium hydroxide and 0.25 g of tetra-n-butylammonium hydrogen sulfate in 200 ml of dry toluene was refluxed for 24 hours. After cooling, the reaction mixture was filtered, and the solvent was evaporated. The product was crystallized from methanol. The yield of 10-ethylphenothiazine (C14H13NS, FW=227.33) was 90%.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07083884B2
Source datasetuspto-grants-2006_08
ORD IDord-625c6e1d30dd4d0a9f0e4279bcd0f5ff
Source noteuspto-grants-2006_08