Back
HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 659016Generated: October 30, 2026

2-Fluoro-4-nitrophenol → HCID 67523891, compound

https://huagongshe.com/reaction/659016

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2-Fluoro-4-nitrophenolHCID 9825—
ReactantSodium hydrideHCID 24758—
ReactantHCID 86639105HCID 86639105—
SolventDimethylformamideHCID 6228—
ProductHCID 67523891HCID 6752389170.2%

Reaction Conditions

Temperature140 °C

Reaction Steps

358 mg (14.2 mmol) 95% sodium hydride was given to a solution of 2.12 g (13.5 mmol) 2-fluoro-4-nitrophenol in 25 ml DMF. Stirring was continued for 30 min. at room temperature. 2.53 g (13.5 mmol) 3-(4-Chloro-pyrimidin-2-ylamino)-propan-1-ol were added and the mixture heated to 140° C. for 24 h. The reaction mixture was evaporated, taken up with water and extracted with dichloromethane. The organic phase was extracted with sodium carbonate solution, dried (sodium sulphate) and evaporated. The obtained material was purified by chromatography over silica (dichloromethane/ethanol 95:5) to give 2.92 g (70%) 3-[4-(2-fluoro-4-nitro-phenoxy)-pyrimidin-2-ylamino]-propan-1-ol as slightly yellow oil.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08080552B2
Source datasetuspto-grants-2011_12
ORD IDord-1e7b34c38c3e4c08b6500de677d98059
Source noteuspto-grants-2011_12