Potassium Hydroxide → (m-Methoxybenzylthio)-terephthalic acid

HRID 66155Notes

Reaction equation

HRID 66155 reaction equation
C([C:4]1[C:5]([C:26]([O-:28])=[O:27])=[C:6](C(C)C)[C:7]([S:13][CH2:14][C:15]2[CH:20]=[CH:19][CH:18]=[C:17]([O:21][CH3:22])[CH:16]=2)=[C:8]([CH:12]=1)[C:9]([O-:11])=[O:10])(C)C.C(C1C(C([O-])=O)=C(C(C)C)C(SCC2C=CC=CC=2)=C(C=1)C([O-])=O)(C)C.[OH-].[K+]>CO.O>[CH3:22][O:21][C:17]1[CH:16]=[C:15]([CH:20]=[CH:19][CH:18]=1)[CH2:14][S:13][C:7]1[CH:6]=[C:5]([C:26]([OH:28])=[O:27])[CH:4]=[CH:12][C:8]=1[C:9]([OH:11])=[O:10]

Participants

6

Reactant 3

HCID 14797Potassium HydroxideHCID 131711379HCID 131711379, compoundHCID 131711380HCID 131711380, compound

Product 1

HCID 22755698(m-Methoxybenzylthio)-terephthalic acidYield 100%

Reagents, catalysts & solvents 2

HCID 887MethanolSolvent2×HCID 962WaterSolvent

Procedure

Following the procedure of Preparation 3(a), but substituting 32 g. of diisopropyl-(m-methoxybenzylthio)-terephthalate for diisopropyl-(benzylthio)-terephthalate, using 350 ml. of methanol, 35 ml. of water and 18 g. of potassium hydroxide, and refluxing for three hours, there is obtained 25.2 g. (yield 100%) of (m-methoxybenzylthio)-terephthalic acid having a melting point of 255°-256° C. after recrystallization from methanol.

Workup

  1. customthere is obtained 25.2 g

Sources & evidence

ORD record
ord-e8451fc362cf4eeda093b4f9ea7b5c2d
Source dataset
uspto-grants-1978_12
Patent number
US04130654

Reaction notes

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