反应详情

The desired compound was prepared according to the procedure of Example 1, step C, using 3-methoxy-1-propanamine as the starting material in 93% yield. LCMS for C7H14N5O3 (M+H)+: m/z=216.1. Step B: N′-Hydroxy-4-[(3-methoxypropyl)amino]-1,2,5-oxadiazole-3-carboximidamide