HRID69811

反应详情

EQUATION

反应方程式

HRID 69811 的结构方程式

PROCEDURE

实验过程

The desired compound was prepared according to the procedure of Example 20, step C, using N-hydroxy-4-(2-methoxyethylamino)-1,2,5-oxadiazole-3-carbimidoyl chloride and 1-(4-chloro-2-furyl)methanamine trifluoroacetate as the starting material in quantitative yield. LCMS calculated for C11H15ClN5O4 (M+H)+: m/z=316.0.