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HRID69840

反应详情

EQUATION

反应方程式

HRID 69840 的结构方程式

REACTANTS

反应物

2
结构：O=[N+]([O-])c1cc(F)ccc1F
HCID67767

2,5-Difluoronitrobenzene

C6H3F2NO2

结构：CC(C)(C)OC(=O)NC1CCNCC1
HCID723833

4-(N-Boc-amino)piperidine

C10H20N2O2

PRODUCTS

生成物

1
结构：CC(C)(C)OC(=O)NC1CCN(c2ccc(F)cc2[N+](=O)[O-])CC1
HCID53255560

未命名化合物

收率 97%

PROCEDURE

实验过程

Method 1 was followed using 2,5-difluoronitrobenzene (1.0 eq), 4-(N-Boc-amino) piperidine (1.4 eq), and TEA (2.0 eq) at 55° C. overnight yielding tert-butyl 1-(4-fluoro-2-nitrophenyl)piperidin-4-ylcarbamate (97%). LCMS (m/z): 340.1 (MH+); LC Rt=3.28 min.

WORKUP

后处理

  1. customat 55° C.
  2. customovernight