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HRID7040

反应详情

EQUATION

反应方程式

HRID 7040 的结构方程式

REACTANTS

反应物

2
结构：COC(=O)c1ccc(CBr)cc1
HCID256687

Methyl 4-(bromomethyl)benzoate

C9H9BrO2

结构：NC(=O)[C@@H]1CCCC[C@@H]1NS(=O)(=O)c1ccc(Cl)cc1
HCID69655699

未命名化合物

PRODUCTS

生成物

1
结构：COC(=O)c1ccc(CN([C@@H]2CCCC[C@@H]2C(N)=O)S(=O)(=O)c2ccc(Cl)cc2)cc1
HCID11202122

未命名化合物

收率 61%

PROCEDURE

实验过程

The titled compound (90 mg) was prepared in 61% yield from cis-2-(4-chlorobenzenesulfonylamino)-cyclohexanecarboxylic acid amide and methyl 4-(bromomethyl)benzoate according to the procedure described in Example 11: 1H NMR (DMSO-d6) δ 7.83 (m, 4 H), 7.64 (d, 2 H, J=8.0 Hz), 7.42 (d, 2 H,J=8.0 Hz), 7.28 (s, 1 H), 6.61 (s, 1 H), 4.64 (AB2,2 H,Δv=20,Jab=72 Hz), 3.85 (m, 4 H), 2.79 (m, 1 H), 2.42 (m, 1 H), 1.78 (m, 1 H), 1.63 (m, 2 H), 1.28 (m, 3 H), 0.90 (m, 1 H); MS m/e 464.98 (M+H)+.