HRID714691

反应详情

EQUATION

反应方程式

HRID 714691 的结构方程式

PROCEDURE

实验过程

70 mg (0.23 mmol) of the compound from Example 5A were reacted with 66 mg (0.23 mmol) of the compound from Example 88A analogously to the preparation of the compound in Example 77. This gave 65 mg (55% of theory) of the title compound.