4-Methoxyphenoxyacetic acid → 1-(4-(2-(4-Fluorophenyl)thiazolo[5,4-d]pyrimidin-7-yl)piperazin-1-yl)-2-(4-methoxyphenoxy)ethanone

HRID 718301Notes

Reaction equation

HRID 718301 reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[S:9][C:10]3[N:11]=[CH:12][N:13]=[C:14]([N:17]4[CH2:22][CH2:21][NH:20][CH2:19][CH2:18]4)[C:15]=3[N:16]=2)=[CH:4][CH:3]=1.[CH3:23][O:24][C:25]1[CH:35]=[CH:34][C:28]([O:29][CH2:30][C:31](O)=[O:32])=[CH:27][CH:26]=1>>[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[S:9][C:10]3[N:11]=[CH:12][N:13]=[C:14]([N:17]4[CH2:22][CH2:21][N:20]([C:31](=[O:32])[CH2:30][O:29][C:28]5[CH:34]=[CH:35][C:25]([O:24][CH3:23])=[CH:26][CH:27]=5)[CH2:19][CH2:18]4)[C:15]=3[N:16]=2)=[CH:4][CH:3]=1

Participants

3

Reactant 2

HCID 746494-Methoxyphenoxyacetic acidHCID 667581752-(4-Fluorophenyl)-7-(piperazin-1-yl)thiazolo[5,4-d]pyrimidine

Product 1

HCID 667587111-(4-(2-(4-Fluorophenyl)thiazolo[5,4-d]pyrimidin-7-yl)piperazin-1-yl)-2-(4-methoxyphenoxy)ethanoneYield 51%

Procedure

This compound was prepared from 2-(4-fluorophenyl)-7-(piperazin-1-yl)thiazolo[5,4-d]pyrimidine using 4-methoxyphenoxyacetic acid in a yield of 51%, according to the procedure for the synthesis of example 50.

Workup

  1. customaccording to the procedure for the synthesis of example 50

Sources & evidence

ORD record
ord-4ab7c7467bc14e3b821e5a665fb7d5fa
Source dataset
uspto-grants-2015_11
Patent number
US09193741B2

Reaction notes

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