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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 726267Generated: October 30, 2026

2-Naphthol → HCID 178419960, compound

https://huagongshe.com/reaction/726267

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2-NaphtholHCID 8663—
ReactantSodium hydrideHCID 24758—
Reactant4-(2-chloroethyl)-1H-imidazole hydrochlorideHCID 178478570—
CatalystTetrabutylammonium IodideHCID 67553—
SolventDimethylformamideHCID 6228—
ProductHCID 178419960HCID 178419960—

Reaction Steps

240 mg (60% in oil, 6 mmol) of sodium hydride are added to a solution of 1.73 g (12 mmol) of 2-naphthol in 10 ml of dimethylformamide. The mixture is stirred at room temperature for 3 hours under nitrogen. 200 mg (1.2 mmol) of 4-(2-chloroethyl)-1H-imidazole hydrochloride and tetrabutylammonium iodide (catalytic amount) are added and the mixture is heated at 100° C. for 3 days and then the solvent is evaporated under reduced pressure. The excess 2-naphthol is extracted with diethyl ether under acidic conditions (dilute hydrochloric acid). The aqueous solution is basified with potassium carbonate and the product is extracted with diethyl ether. The ethereal extracts are concentrated and the residue obtained is crystallized from a methanol/water (1/2) mixture, M.p.: 157°-158° C.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05708171
Source datasetuspto-grants-1998_01
ORD IDord-7928c8c1985442f0a3a84c8841feed17
Source noteuspto-grants-1998_01