Back
HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 727236Generated: October 30, 2026

Phenothiazine → 10-(3-chloropropyl)-10H-phenothiazine

https://huagongshe.com/reaction/727236

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPhenothiazineHCID 7108—
Reactant1-Bromo-3-chloropropaneHCID 8006—
ReactantSodium hydrideHCID 24758—
ReactantAmmonium ChlorideHCID 25517—
SolventDimethylformamideHCID 6228—
Product10-(3-chloropropyl)-10H-phenothiazineHCID 1229912080%

Reaction Steps

To a solution of phenothiazine (4.0 g, 0.02 mol) in dry dimethylformamide (100 ml) kept under an atmosphere of nitrogen, sodium hydride (1.0 g, 0.025 mol, 60% dispersion in oil) was carefully added. The reaction mixture was left stirring for 15 minutes. 1-Bromo-3-chloropropane (8.0 g, 0.05 mol) was added and the mixture was left stirring overnight. Ammonium chloride (2.0 g, 0.04 mol) was added, and after continued stirring for 30 minutes the solution was poured onto water (300 ml). The mixture was extracted with dichloromethane (2×200 ml). The combined organic extracts were dried (MgSO4), filtered and the solvent evaporated. This afforded a residue which was purified by column chromatography on silica gel (250 g) using a mixture of n-heptane and ethyl acetate (9:1) as eluent. 4.4 g (80%) of 10-(3-chloropropyl)-10H-phenothiazine was obtained as an oil. Rf : 0.55 (SiO2 ; n-heptane/ethyl acetate=1:1).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05712292
Source datasetuspto-grants-1998_01
ORD IDord-997ad8ed80e34f909dbd16f59fa4e8ca
Source noteuspto-grants-1998_01