HRID730042

反应详情

EQUATION

反应方程式

HRID 730042 的结构方程式

REACTANTS

反应物

2

结构：Cc1ccnc(F)c1

2-Fluoro-4-methylpyridine

C6H6FN

结构：O=C(Cc1ccnc(Cl)c1)c1ccc(F)cc1

2-(2-chloropyridin-4-yl)-1-(4-fluorophenyl)ethanone

C13H9ClFNO

PRODUCTS

生成物

1

结构：O=C(Cc1ccnc(F)c1)c1ccc(F)cc1

1-(4-fluorophenyl)-2-(2-fluoropyridin-4-yl)ethanone

C13H9F2NO

PROCEDURE

实验过程

21b was prepared from 2-fluoro-4-methylpyridine (13.9 g; 125 mmol) using the method described in the synthesis of 21a.