Hydrochloric Acid → 5-(Methyl-propylcarbamoyl)-isophthalic acid monoethyl ester

Participants

Reaction Steps

Stir a solution of 5-(methyl-propylcarbamoyl)-isophthalic acid diethyl ester (2.02 g, 6.3 mmol), NaOH (0.25 g, 6.3 mmol) and ethanol (32 mL) at room temperature overnight. Add 0.2 N HCl (60 mL) and extract with ethyl acetate (2×50 mL). Dry (magnesium sulfate), concentrate and purify (silica gel chromatography, eluting with 50:50 ethyl acetate:hexanes with 1% acetic acid then 100% ethyl acetate with 1% acetic acid) to give the title compound as an oil (1.4 g, 75%).

Provenance & Evidence