HRID735515

反应详情

EQUATION

反应方程式

HRID 735515 的结构方程式

PROCEDURE

实验过程

Using a procedure analogous to that used to prepare 2B, 10D (431 mg, 0.869 mmol) was reacted with NaOH to give 10E (263 mg, 71%) as a brown solid. 1H NMR (400 MHz, THF-d8) δ 1.34 (s, 9 H), 1.96-2.07 (m, 2 H), 2.35 (t, J=7.25 Hz, 2 H), 2.69 (t, J=7.25 Hz, 2 H), 7.09 (s, 1 H), 7.16 (d, J=7.91 Hz, 2 H), 7.71 (d, J=8.35 Hz, 2 H), 7.92-7.96 (m, 1 H), 8.01 (dd, J=2.20 Hz, 1 H), 8.23 (d, J=2.20 Hz, 1 H), 9.69-9.77 (m, 1 H).