HRID79233

反应详情

EQUATION

反应方程式

HRID 79233 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

To a solution of compound 403 (1.43 g, 3.05 mmol) in ethanol (27 mL) was added palladium hydroxide, 20 wt % pd (dry basis) on carbon, wet (1.51 g, 2.15 mmol), followed by hydrochloric acid (0.10 mL). The sealed glass tube was then evacuated and purged with hydrogen three times. The sealed tube was then charged with hydrogen (50 psi), and allowed to stir at room temperature for three days. HPLC showed ˜85% conversion to the desired product. After filtering the mixture through a plug of celite, the filtrate was concentrated to a solid and purified by flash chromatography (0-20% methanol in DCM with 1% NH4OH) to give compound 404 (709 mg, 61%) as a white solid. LCMS-ESI (POS), M/Z, M+1: Found 379.1, Calculated 379.2.

WORKUP

后处理

  1. dry with materialpalladium hydroxide, 20 wt % pd (dry basis) on carbon, wet (1.51 g, 2.15 mmol)
  2. customThe sealed glass tube was then evacuated
  3. custompurged with hydrogen three times
  4. additionThe sealed tube was then charged with hydrogen (50 psi)
  5. filtrationAfter filtering the mixture through a plug of celite
  6. concentrationthe filtrate was concentrated to a solid
  7. custompurified by flash chromatography (0-20% methanol in DCM with 1% NH4OH)