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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 8002Generated: October 25, 2026

(Bromomethyl)cyclopentane → 2-cyclopentylmethyl-6-(3-fluoro-4-methoxyphenyl)-4-methoxycarbonyl-2H-pyridazin-3-one

https://huagongshe.com/reaction/8002

Reaction equation

Participants

RoleNameHCIDCharge
Reactant(Bromomethyl)cyclopentaneHCID 12723264—
Reactant6-(3-fluoro-4-methoxyphenyl)-4-methoxycarbonyl-2H-pyridazin-3-oneHCID 21991432—
Reactant6-(2,4-difluorophenyl)-4-hydroxymethyl-2-isobutyl-2H-pyridazin-3-oneHCID 21991662—
Product2-cyclopentylmethyl-6-(3-fluoro-4-methoxyphenyl)-4-methoxycarbonyl-2H-pyridazin-3-oneHCID 2199165172%

Reaction Steps

Following the procedure of Example 1 (6), 6-(3-fluoro-4-methoxyphenyl)-4-methoxycarbonyl-2H-pyridazin-3-one and cyclopentylmethyl bromide {J. Org. Chem., 36, 3103 (1971)} were reacted to yield the title compound as yellow needles (yield: 72.0%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07087606B2
Source datasetuspto-grants-2006_08
ORD IDord-70106503310b486f9426aa13d75982e5
Source noteuspto-grants-2006_08