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HRID80524

反应详情

EQUATION

反应方程式

HRID 80524 的结构方程式

REACTANTS

反应物

2
结构：CO.Cl
HCID21893726

Hydrochloride methanol

CH5ClO

结构：CC(C)(C)OC(=O)N1CC[C@@H]2c3ccccc3C(=O)NC[C@@H]2C1
HCID67249978

未命名化合物

PRODUCTS

生成物

1
结构：O=C1NC[C@@H]2CNCC[C@@H]2c2ccccc21
HCID49763200

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CCOCC
溶剂HCID3283

Diethyl Ether

C4H10O

PROCEDURE

实验过程

To a suspension of Example 180G in 400 mL of diethyl ether was added 80 mL of HCl/methanol (5N) at 25° C. The mixture was stirred overnight. The solid formed was collected and dried to obtain the title compound as the hydrochloride salt.

WORKUP

后处理

  1. customThe solid formed
  2. customwas collected
  3. customdried