3,5-Heptanedione → HCID 514307, compound

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Reaction Steps

[I; Ar is 3,4-methylenedioxyphenyl, R0 is H, R' and R" are CH3CH2CO, Y is CH=CHCH2CH2 ] was prepared from 12.5 g. of 6-(3,4-methylenedioxyphenyl)-3-hexenyl iodide (Preparation D2) and 12.5 g. of the lithium salt of 3,5-heptanedione in 175 ml. of dimethylformamide. The product was chromatographed on silica gel and eluted with pentane-benzene (1:1) and then with chloroform-benzene (7:3). The latter brought out 7.0 g. of 4-[6-(3,4-methylenedioxyphenyl)-3-hexenyl]-3,5-heptanedione as a light amber oil.

Provenance & Evidence