Formaldehyde → Formaldehyde;phenol

HRID 845110Notes

Reaction equation

HRID 845110 reaction equation
[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.C=O.C(O)(=O)C(O)=O>>[CH2:1]=[O:7].[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1

Participants

4

Reactant 3

HCID 712FormaldehydeHCID 971Oxalic AcidHCID 996Phenol

Product 1

HCID 172281Formaldehyde;phenol

Procedure

Using the procedure described in Example 7-A, 3000 grams (31.88 moles) of phenol was reacted with 1655.96 grams (20.4 moles) of formalin (37% aqueous formaldehyde) using 15.0 grams (0.167 mole) of oxalic acid. The solid resin obtained had a Mettler softening point of 92.7, and a metl viscosity of 380 cps at 150° C. By GPC analysis, the wt. avg. M.W. was 1,168, no. avg. M.w. 753, with a polydispersity of 1.55. The resin contained 16.67% 2-functional product. The weight ratio of 2-functional to 3-functional components was 1.24:1.

Workup

  1. customThe solid resin obtained
  2. customat 150° C

Sources & evidence

ORD record
ord-2ec6812bbdc04344b9a946da82a4e106
Source dataset
uspto-grants-1988_07
Patent number
US04755543

Reaction notes

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