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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 847066Generated: October 30, 2026

Sodium Iodide → Ethyl 3-(4-methylphenyl)-3-oxo-2-(allyl)propanoate

https://huagongshe.com/reaction/847066

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium IodideHCID 5238—
ReactantAllyl bromideHCID 7841—
ReactantEthyl 3-(4-methylphenyl)-3-oxopropanoateHCID 292637—
ReactantSodium ethoxideHCID 2723922—
ProductEthyl 3-(4-methylphenyl)-3-oxo-2-(allyl)propanoateHCID 1569811397.5%

Reaction Steps

Ethyl 3-(4-methylphenyl)-3-oxopropanoate (prepared as described in W. Wierenga and H. I. Skulnick, J. Org. Chem. (1979), 44, 310) (63.66 g, 309 mmol, 1 eq) was added to a freshly prepared sodium ethoxide solution (Na, 7.43 g, 323 mmol, 1.05 eq; EtOH, 250 mL). The ethanol was removed in vacuo and the residue was dissolved in DMF (250 mL). Allyl bromide (29.3 mL, 338 mmol, 1.1 eq) followed by sodium iodide (4.56 g, 304 mmol, 1 eq) were then added and the contents stirred overnight at room temperature. The DMF was removed in vacuo, water (250 mL) was added and the aqueous layer extracted with ethyl acetate (3×200 mL). The organic layers were dried (MgSO4) and the solvent removed in vacuo to yield 74.21 g of an amber oil. NMR (200 MHz, CDCl3) δ7.81 (d, 2H, J=10 Hz); 7.30 (d, 2H, J=10 Hz); 5.96-5.72 (m, 1H); 5.21-5.00 (m, 2H); 4.41 (t, 1H, J=7 Hz); 4.16 (q, 2H, J=7 Hz); 2.78 (t, 2H, J=7 Hz); 2.42 (s, 3H); 1.18 (t, 3H, J=7 Hz). Anal. Calcd. for C15H18O3 : C, 73.15; H, 7.37. Found: C, 73.10; H, 7.38.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05138069
Source datasetuspto-grants-1992_08
ORD IDord-499effcc12d842abbf7dda768b56687f
Source noteuspto-grants-1992_08