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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 849362Generated: October 25, 2026

4-Bromodiphenyl Ether → 1-(4-Phenoxyphenyl)propan-2-one

https://huagongshe.com/reaction/849362

Reaction equation

Participants

RoleNameHCIDCharge
Reactant4-Bromodiphenyl EtherHCID 7565—
ReactantIsopropenyl acetateHCID 7916—
ReactantPotassium FluorideHCID 522689—
ReactantMethoxytri-n-butylstannaneHCID 11964040—
SolventTolueneHCID 1140—
Product1-(4-Phenoxyphenyl)propan-2-oneHCID 1959152383%

Reaction Steps

75.0 g of 4-bromodiphenyl ether, 129 ml of tributyltin methoxide, 45.0 g of isopropenyl acetate and 2,47 g of dichlorobis{tri(o-tolyl)phosphine}palladium, were dissolved in 300 ml of toluene and refluxed under heating for 3 hours. The reaction solution was left to cool to room temperature, and then, a saturated potassium fluoride aqueous solution was added, followed by stirring for one hour. Then, the product was subjected to celite filtration and washed with ethyl acetate. The filtrate and washing liquid were put together. Then, the organic layer was separated and washed with a saturated sodium chloride aqueous solution and then dried over anhydrous magnesium sulfate. The drying agent was filtered off, and then, the solvent was distilled off under reduced pressure. The residue was purified by silica gel column chromatography (hexane/ethyl acetate=15/1→10/1) to obtain 56.3 g (yield: 83%) of the above identified compound as yellow solid.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06011174
Source datasetuspto-grants-2000_01
ORD IDord-16f48f99f052458ab881bcbd42a77a81
Source noteuspto-grants-2000_01