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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 852632Generated: October 31, 2026

Ethanol → 2-(3-Methoxyphenyl)-2-propanamine

https://huagongshe.com/reaction/852632

Reaction equation

Participants

RoleNameHCIDCharge
ReactantEthanolHCID 702—
ReactantBenzyl [1-(3-methoxyphenyl)-1-methylethyl]carbamateHCID 67264266—
CatalystPalladiumHCID 23938—
SolventWaterHCID 962—
Product2-(3-Methoxyphenyl)-2-propanamineHCID 1391131053%

Reaction Conditions

Temperature80 °C

Reaction Steps

A flask was charged with [1-(3-methoxy-phenyl)-1-methyl-ethyl]-carbamic acid benzyl ester (D100) (1 g, 3.34 mmol, 1 equiv), 10% palladium on charcoal (50% wet, 100 mg, 10% w/w), NH4COOH (2.1 g, 33 mmol, 10 equiv), EtOH (40 ml) and H2O (8 ml). The resulting mixture was stirred at 80° C. for 2 h, cooled to room temperature and the catalyst was filtered off using a pad of celite. Most of the EtOH was removed in vacuo and the residue was diluted with 1N HCl aqueous solution. The aqueous phase was extracted with AcOEt then basified to pH 13 and extracted twice with AcOEt. These combined organic layers were dried over MgSO4 and concentrated in vacuo to yield 1-(3-methoxy-phenyl)-1-methyl-ethylamine (F15) (290 mg, 53%) as a yellow gum.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07253198B2
Source datasetuspto-grants-2007_08
ORD IDord-656430813be44272a8ac4c1e692987aa
Source noteuspto-grants-2007_08