Potassium Hydroxide → HCID 58930469, compound
Reaction equation
C[O:2][C:3](=[O:32])[C:4]1[CH:9]=[CH:8][C:7]([O:10][C@H:11]2[CH2:15][CH2:14][N:13]([C:16]3[CH:21]=[CH:20][C:19]([C:22](=[O:31])[NH:23][C:24]4[CH:29]=[CH:28][CH:27]=[CH:26][C:25]=4[NH2:30])=[CH:18][CH:17]=3)[CH2:12]2)=[CH:6][CH:5]=1.[OH-].[K+]>C1COCC1.O.CO>[NH2:30][C:25]1[CH:26]=[CH:27][CH:28]=[CH:29][C:24]=1[NH:23][C:22]([C:19]1[CH:18]=[CH:17][C:16]([N:13]2[CH2:14][CH2:15][C@H:11]([O:10][C:7]3[CH:6]=[CH:5][C:4]([C:3]([OH:32])=[O:2])=[CH:9][CH:8]=3)[CH2:12]2)=[CH:21][CH:20]=1)=[O:31]Participants
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
A solution of 372 (100 mg, 0.23 mmol) and KOH (100 mg, 1.78 mmol) in 1:1:1 mixture of THF/water/MeOH (6 mL) was stirred at room temperature for 5 days. The reaction mixture was concentrated and partitioned between water (5 mL) and ether (5 mL). Organic phase was discarded and the aqueous phase was acidified to pH=6 using 1M HCl solution and extracted with EtOAc. The extract was dried over Na2SO4, filtered and concentrated. The residue was purified by flash chromatography, eluent MeOH-DCM (gradient of MeOH from 5 till 20% MeOH) to afford the title compound (20 mg, 21% yield). 1H NMR (DMSO) δ 9.34 (σ, 1H), 7.85 (m, 4H), 7.11 (d, 1H, J=7.8 Hz), 7.00 (d, J=8.4 Hz, 2H), 6.92 (d, 2H, J=7.7 Hz), 6.75 (d, J=8.0 Hz, 2H), 6.6 (m, 3H), 5.26 (br.s., 1H), 3.75 (m, 1H), [3.34 DMSO, 4H], 2.44 (m, 1H), 2.31 (m, 1H) m/z: 418.4 (MH+).
Workup
- concentrationThe reaction mixture was concentrated
- custompartitioned between water (5 mL) and ether (5 mL)
- extractionextracted with EtOAc
- dry with materialThe extract was dried over Na2SO4
- filtrationfiltered
- concentrationconcentrated
- customThe residue was purified by flash chromatography, eluent MeOH-DCM (gradient of MeOH from 5 till 20% MeOH)
Sources & evidence
- ORD record
- ord-8621c726f2d847dcbda150d3b9dc1af2
- Source dataset
- uspto-grants-2007_08
- Patent number
- US07253204B2
Reaction notes
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