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HRID85742

反应详情

EQUATION

反应方程式

HRID 85742 的结构方程式

REACTANTS

反应物

2
结构：CC(=O)Cl
HCID6367

Acetyl chloride

C2H3ClO

结构：C=C(C)[C@@H]1CC[C@]2(NCCN3CCN(S(=O)(=O)C4CC4)CC3)CC[C@]3(C)[C@H](CC[C@@H]4[C@@]5(C)CC=C(c6ccc(C(=O)O)cc6)C(C)(C)[C@@H]5CC[C@]43C)[C@@H]12
HCID60152624

未命名化合物

PRODUCTS

生成物

1
结构：C=C(C)[C@@H]1CC[C@]2(NCCN3CCN(C(C)=O)CC3)CC[C@]3(C)[C@H](CC[C@@H]4[C@@]5(C)CC=C(c6ccc(C(=O)O)cc6)C(C)(C)[C@@H]5CC[C@]43C)[C@@H]12
HCID68358148

未命名化合物

PROCEDURE

实验过程

The title compound was prepared following the method described above for the synthesis of 4-((1R,3aS,5aR,5bR,7aR,11aS,11bR,13aR,13bR)-3a-((2-(4-(cyclopropylsulfonyl)piperazin-1-yl)ethyl)amino)-5a,5b,8,8,11a-pentamethyl-1-(prop-1-en-2-yl)-2,3,3a,4,5,5a,5b,6,7,7a,8,11,11a,11b,12,13,13a,13b-octadecahydro-1H-cyclopenta[a]chrysen-9-yl)benzoic acid using acetyl chloride as the reagent in Step 1. The product was isolated as a white solid (5.4 mg, 35%). LCMS: m/e 684.67 (M+H)+, 2.27 min (method 11). 1H NMR (400 MHz, Acetic) δ 7.99 (d, J=8.3 Hz, 2H), 7.26 (d, J=8.5 Hz, 2H), 5.33 (d, J=4.8 Hz, 1H), 4.82 (s, 1H), 4.72 (s, 1H), 4.09-3.89 (m, 1H), 3.85 (br. s., 3H), 3.68 (br. s., 4H), 3.53-3.14 (m, 4H), 2.92-2.66 (m, 1H), 2.28-1.01 (m, 22H), 2.17 (s, 3H), 1.73 (s, 3H), 1.18 (s, 3H), 1.10 (s, 3H), 1.05 (s, 3H), 0.98 (s, 3H), 0.96 (s, 3H).