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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 863810Generated: October 31, 2026

HCID 19420475, compound → 1-(4-Nitrobenzyl)piperazine

https://huagongshe.com/reaction/863810

Reaction equation

Participants

RoleNameHCIDCharge
ReactantHCID 19420475HCID 19420475—
SolventSodium HydroxideHCID 14798—
Product1-(4-Nitrobenzyl)piperazineHCID 9398278%

Reaction Steps

Following the procedure of Example 6, but replacing 1-benzylpiperazine with 1-[4-nitrobenzyl]piperazine, provided the desired compound. To a solution of piperazine (2 g, 0.023 mol) in 10 mL of ethanol added a solution of 4-nitrobenzyl bromide (5 g, 0.023 mol) in 20 mL of warm ethanol. It was gently refluxed for 1 hour and stirred at room temperature for one over night. The resulting white precipitate was filtered, washed with a small amount of cold ethanol, and dried to yield 1-[4-nitrobenzyl]piperazine hydrobromide (3 g). MS m/z M+H=222, H1 --NMR (in MeOH-d4) δ=2.7 (t, 4H, piperazine), 3.25 (t, 4H, piperazine), 3.75 (s, 2H, benzyl), 7.62 (d, 2H, aromatic), 8.20 (d, 2H, aromatic). The obtained 1-[4-nitrobenzyl]piperazine hydrobromide (3 g, 9.93 mmol) was dissolved in 60 mL of 3N sodium hydroxide aqueous solution and stirred at room temperature for 30 minutes. The product was extracted with ethyl acetate (50 mL×3), and the combined ethyl acetate layer was washed with brine, dried over anhydrous sodium sulfate. Solvent was removed to obtain 1.7 g of 1-[4-nitrobenzyl]piperazine in 78% yield. MS m/z M+H=222, H1 -NMR (in MeOH-d4) δ=2.45 (t, 4H, piperazine), 2.90 (t, 4H, piperazine), 3.55 (s, 2H, benzyl), 7.52 (d, 2H, aromatic), 8.50 (d, 2H, aromatic).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05561140
Source datasetuspto-grants-1996_10
ORD IDord-b9c3d8a53f5342b2a369b09774aeb973
Source noteuspto-grants-1996_10