Triethylene Glycol → HCID 74088092, compound

Participants

Reaction Steps

To a small beaker was added 34.2 g (0.20 mole) of crude morpholinomethacrylic acid (Example II compound) and 60 ml methanol. The mixture was stirred until a clear solution resulted. Then, a solution of 12.3 g (0.20 mole) 91% potassium hydroxide in 50 ml methanol was added. The resulting solution was only slightly basic (pH = 8-9). Triethyleneglycol, 40 g, was added and the resulting solution was stripped on a rotary evaporator to remove methanol and water. A slightly viscous solution, that was 51% by weight of the title salt, was obtained.

Provenance & Evidence