tert-Butanol → HCID 51031089, compound

HRID 879027Notes

Reaction equation

HRID 879027 reaction equation
C(O)(C)(C)C.[CH2:6]([O:8][C:9]([NH:11][C@H:12]([C:21]1[CH:26]=[CH:25][CH:24]=[CH:23][CH:22]=1)[C@H:13]([OH:20])[C:14]([O:16][CH:17]([CH3:19])[CH3:18])=[O:15])=[O:10])[CH3:7].[CH2:27]([O:29][C:30]([NH:32][C@@H:33]([C@H:40]([OH:47])[C:41]1[CH:46]=[CH:45][CH:44]=[CH:43][CH:42]=1)[C:34]([O:36][CH:37]([CH3:39])[CH3:38])=[O:35])=[O:31])[CH3:28]>O>[CH2:6]([O:8][C:9]([NH:11][C@H:12]([C:21]1[CH:26]=[CH:25][CH:24]=[CH:23][CH:22]=1)[C@H:13]([OH:20])[C:14]([O:16][CH:17]([CH3:19])[CH3:18])=[O:15])=[O:10])[C:7]1[CH:42]=[CH:41][CH:40]=[CH:33][CH:34]=1.[CH2:27]([O:29][C:30]([NH:32][C@@H:33]([C@H:40]([OH:47])[C:41]1[CH:46]=[CH:45][CH:44]=[CH:43][CH:42]=1)[C:34]([O:36][CH:37]([CH3:39])[CH3:38])=[O:35])=[O:31])[C:28]1[CH:22]=[CH:21][CH:12]=[CH:13][CH:14]=1

Participants

6

Procedure

tert-BuOH (36 mL) and water (12 mL) following the procedure outlined for the preparation of 11a and 11b (vide supra) to yield 12a (175 mg, 9%) and 12b (175 mg, 9%) as off-white solids, and a 1:1 mixture of 12a and 12b (1.45 g, 77%).

Sources & evidence

ORD record
ord-983b56d9cb7f437588b1cf1e24d463b5
Source dataset
uspto-grants-2015_03
Patent number
US08987504B2

Reaction notes

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