HRID882594

反应详情

EQUATION

反应方程式

HRID 882594 的结构方程式

PROCEDURE

实验过程

The title compound was prepared in analogy to the synthesis of Intermediate 61, by reaction of 15 mg of N-methyl-L-valyl-N-[(3R,4S,5S)-3-methoxy-1-{(2S)-2-[(1R,2R)-1-methoxy-2-methyl-3-{[(1S,2R)-1-(1,2-oxazinan-2-ylcarbonyl)-2-phenylcyclopropyl]amino}-3-oxopropyl]pyrrolidin-1-yl}-5-methyl-1-oxoheptan-4-yl]-N-methyl-L-valinamide trifluoroacetate (Intermediate 16) with 4-formylbenzoic acid.