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HRID891410

反应详情

EQUATION

反应方程式

HRID 891410 的结构方程式

REACTANTS

反应物

2
结构：CC(C)(O)CCO
HCID247470

1,3-Butanediol, 3-methyl-

C5H12O2

结构：O=c1c(Br)c(Br)cnn1-c1ccc(F)c(F)c1
HCID15941889

4,5-Dibromo-2-(3,4-difluorophenyl)pyridazin-3(2H)-one

C10H4Br2F2N2O

PRODUCTS

生成物

1
结构：CC(C)(O)CCOc1c(Br)cnn(-c2ccc(F)c(F)c2)c1=O
HCID21934227

5-Bromo-2-(3,4-difluorophenyl)-4-(3-hydroxy-3-methylbutoxy)pyridazin-3(2H)-one

C15H15BrF2N2O3

PROCEDURE

实验过程

The dibromo-intermediate from Example 471B was reacted according to the procedure described in Example 194B, substituting 3-methyl-1,3-butanediol in place of methanol, to selectively react at the 4-position and provide the title intermediate.

WORKUP

后处理

  1. customto selectively react at the 4-position