Methyl dichloroacetate → HCID 11417514, compound

Participants

Reaction Steps

Methyl dichloroacetate (23.2 g, 5 eq ) and triethylamine (33.0 g, 10 eq) was added to a solution of 17 (8.64 g) in 50 ml of MeOH at room temperature. The reaction mixture was stirred overnight. Methanol was removed in vacuo. The residue was dissolved in 250 ml of ethyl acetate and washed with 1N HCl. The organic layer was washed with a 10% solution of sodium bicarbonate and brine and dried over sodium sulfate and concentrated to dryness. After purification via a column, 11.7 g of the desired product was obtained as a white solid.

Provenance & Evidence