Ethanethiol → 6-fluoro-1-(4-methoxy-benzyl)-1H-pyrido[2,3-d][1,3]oxazine-2,4-dione

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Reaction Steps

2,6 Dichloro-5-fluoro-nicotinic acid was selected as a starting material to make the compounds of structure (Ia) with fluoro substitution at 6-position of naphthyridine moiety. 2,6 Dichloro-5-fluoro-nicotinic acid was esterified by treating with thionyl chloride followed by refluxing with dry ethanol to yield 2,6-dichloro-5-fluoro-nicotinic acid ethyl ester, depicted by formula 21 in Scheme 10. This ester gave 2-chloro-6-ethylsulfanyl-5-fluoro-nicotinic acid ethyl ester, depicted by formula 22 in Scheme 10, when reacted with ethanethiol and sodium hydride. 6-Ethylsulfanyl-5-fluoro-2-(4-methoxy-benzylamino)-nicotinic acid ethyl ester, depicted by formula 23 in Scheme 10, was prepared by amination of 2-chloro-6-ethylsulfanyl-5-fluoro-nicotinic acid ethyl ester, which was converted into 5-fluoro-2-(4-methoxy-benzylamino)-nicotinic acid ethyl ester, depicted by formula 24 in Scheme 10, by refluxing with ethanol and raney nickel. 5-Fluoro-2-(4-methoxy-benzylamino)-nicotinic acid ethyl ester was then reacted with trichloromethylchloroformate to yield 6-fluoro-1-(4-methoxy-benzyl)-1H-pyrido[2,3-d][1,3]oxazine-2,4-dione, depicted by formula 25 in Scheme 10. The sequence of reactions is shown in Scheme 10.

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