Sodium hydride → HCID 86634728, compound

Participants

Reaction Steps

Using the method of Example 3, Step A, 2,6-difluorophenol (821 mg, 6.31 mmol), 60% sodium hydride in mineral oil (252 mg, 6.31 mmol), and 2-chloro-4-nitropyridine (1.00 g, 6.31 mmol) were reacted to provide 2-chloro-4-(2,6-difluorophenoxy)pyridine (1.44 g, 94% yield) as an oil. 1H NMR (CDCl3) δ 8.27 (d, 1H), 7.26 (m, 1H), 7.04-7.10 (m, 2H), 6.80-6.86 (m, 2H).

Provenance & Evidence