Sodium hydride → 2-Chloro-4-(2,6-dimethylphenylthio)pyridine

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Reaction Steps

Using the method of Example 3, Step A, 2,6-dimethylbenzenethiol (0.872 g, 6.31 mmol), 60% sodium hydride in mineral oil (252 mg, 6.31 mmol), and 2-chloro-4-nitropyridine (1.00 g, 6.31 mmol) were reacted to provide 2-chloro-4-(2,6-dimethylphenylthio)pyridine (1.35 g, 86% yield) as a white solid. 1H NMR (CDCl3) δ 8.07 (d, 1H), 7.22-7.34 (m, 3H), 6.75 (s, 1H), 6.71 (d, 1H), 2.40 (s, 6H).

Provenance & Evidence