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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 911535Generated: October 30, 2026

Potassium Iodide → HCID 66707197, compound

https://huagongshe.com/reaction/911535

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPotassium IodideHCID 4875—
ReactantPotassium CarbonateHCID 11430—
Reactant4-Benzyloxybenzyl chlorideHCID 70042—
Reactant3-tert-butoxycarbonyl-7-chloro-6-mercapto-2,3,4,5-tetrahydro-1H-benzo[d]azepineHCID 66706900—
SolventAcetoneHCID 180—
ProductHCID 66707197HCID 6670719767.3%

Reaction Steps

Dissolve 3-tert-butoxycarbonyl-7-chloro-6-dimethylcarbamoylthio-2,3,4,5-tetrahydro-1H-benzo[d]azepine (706 mg, 1.84 mmol) in methanol (20 mL). Add potassium hydroxide (3.5 g, 55 mmol) and heat the mixture at reflux for 3h. Cool to ambient temperature. Pour reaction in saturated aqueous NH4Cl solution. Extract three times with EtOAc. Combine organic extracts, dry over Na2SO4 and concentrate in vacuo to obtain crude 3-tert-butoxycarbonyl-7-chloro-6-mercapto-2,3,4,5-tetrahydro-1H-benzo[d]azepine (602 mg, 100%). Dissolve 3-tert-butoxycarbonyl-7-chloro-6mercapto-2,3,4,5-tetrahydro-1H-benzo[d]azepine (282 mg, 0.9 mmol) in acetone (30 mL). Add 4-benzyloxybenzyl chloride (251 mg, 1.08 mmol), potassium carbonate (powder) (373 mg, 2.7 mmol) and potassium iodide (powder) (15 mg, 0.1 mmol) and reflux for 16 h. Cool the reaction to ambient temperature, dilute with acetone, filter and concentrate in vacuo. Purify by chromatography on silica gel eluting with hexane/EtOAc (1:0 and 17:3) to give 6-(4-benzyloxybenzylthio)-3-tert-butoxycarbonyl-7-chloro-2,3,4,5-tetrahydro-1H-benzo[d]azepine (309 mg, 67%). MS (ES+) m/z: 510 (M+H)+.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08022062B2
Source datasetuspto-grants-2011_09
ORD IDord-53d25670ee1b49a297677987006fe6e1
Source noteuspto-grants-2011_09