4-Fluoroaniline → HCID 59540253, compound

HRID 923439Notes

Reaction equation

HRID 923439 reaction equation
[F:1][C:2]1[CH:8]=[CH:7][C:5]([NH2:6])=[CH:4][CH:3]=1.[CH3:9][O:10][C:11]1[CH:18]=[CH:17][C:14]([CH2:15]Br)=[CH:13][C:12]=1[N+:19]([O-:21])=[O:20]>>[F:1][C:2]1[CH:8]=[CH:7][C:5]([N:6]([CH2:15][C:14]2[CH:17]=[CH:18][C:11]([O:10][CH3:9])=[C:12]([N+:19]([O-:21])=[O:20])[CH:13]=2)[CH2:15][C:14]2[CH:17]=[CH:18][C:11]([O:10][CH3:9])=[C:12]([N+:19]([O-:21])=[O:20])[CH:13]=2)=[CH:4][CH:3]=1

Participants

3

Reactant 2

HCID 97314-FluoroanilineHCID 115796484-(Bromomethyl)-1-methoxy-2-nitrobenzene

Product 1

HCID 59540253HCID 59540253, compoundYield 91%

Procedure

4-Fluoroaniline and 4-methoxy-3-nitrobenzyl bromide were processed using the method described in Example 1A to provide 2.33 g (91%) of the title compound. MS (ESI; M+H) m/z=442.

Sources & evidence

ORD record
ord-5c55c0737af64c2da24418ad4ed5397c
Source dataset
uspto-grants-2016_03
Patent number
US09278922B2

Reaction notes

Loading…