Benzene → Nitrobenzene
Reaction equation
[N+:1]([O-:4])(O)=[O:2].[CH:5]1[CH:10]=[CH:9][CH:8]=[CH:7][CH:6]=1>>[N+:1]([C:5]1[CH:10]=[CH:9][CH:8]=[CH:7][CH:6]=1)([O-:4])=[O:2]Participants
3
Reactant 2
Product 1
Procedure
The benzene excess based on nitric acid of 2.0% to 20%, preferably of 5.0% to 10% of theory, refers to the molar ratio of benzene and nitric acid. Theoretically one mol of nitric acid reacts with one mol of benzene to give one mol of nitrobenzene.
Sources & evidence
- ORD record
- ord-9f8268a404f44bdfb32731c6f43280e5
- Source dataset
- uspto-grants-2016_03
- Patent number
- US09284255B2
Reaction notes
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