HRID930055

反应详情

EQUATION

反应方程式

HRID 930055 的结构方程式

PROCEDURE

实验过程

9 mg (0.03 mmol) of the compound of Example 27A is reacted analogously to the synthesis of the compound of Example 1 with 4 mg (0.03 mmol) of 4-imidazolinone-hydrochloride. 4 mg (35% of theory) of the title compound is obtained.