HRID930098

反应详情

EQUATION

反应方程式

HRID 930098 的结构方程式

PROCEDURE

实验过程

80 mg (0.21 mmol) of the compound of Example 50A is reacted analogously to the synthesis of the compound of Example 1 with 29 mg (0.24 mmol) of 4-imidazolinone-hydrochloride. 76 mg (79% of theory) of the title compound is obtained.