Hydrochloric Acid → HCID 20202544, compound

Participants

Reaction Steps

The procedure of Example 1 is repeated, using 35.5 parts (0.5 mole) of acrylamide in 100 parts of deionised water, adding 53 parts (0.5 mole) of 2-mercaptopropionic acid over 20 minutes, adjusting the pH of the reaction mixture to 10.0 with 90 parts of 30% aqueous sodium hydroxide solution, and adding 15 parts (0.5 mole) of paraformaldehyde to the reaction mixture at pH 9.5 after addition of hydrochloric acid. Yield: 304 parts of a 43% aqueous, slightly viscous yellowish solution to the methylolated reaction product of formula ##STR14##

Provenance & Evidence