反应详情

This compound was prepared according to General Method 11 (EXAMPLE 22) from (4-amino-2-methoxyphenyl)-(4-methoxybenzyl)amine (1.23 g, 4.76 mmol) and ethyl 4,4,4-trifluoroacetoacetate (1.05 g, 5.71 mmol) in 60 mL benzene followed by treatment with 10 mL concentrated H2SO4 to afford 0.734 (60%) of 6-amino-7-methoxy-4-(trifluoromethyl)-1H-quinolin-2-one, a yellow solid, after rinsing with MeOH:ether:hexanes. Data for 6-amino-7-methoxy-4-(trifluoromethyl)-1H-quinolin-2-one: Rf 0.28 (19:1 CH2Cl2:MeOH); 1H NMR (500 MHz, CDCl3) δ 12.2 (v broad s, 1H), 7.06 (broad s, 1H), 6.93 (s, 1H), 6.79 (s, 1H), 4.01 (s, 3H), 3.94 (broad s, 2H).

1. customThis compound was prepared