三乙胺盐酸盐 → HCID 178440084，化合物

反应方程式

[C:1]([C:3]1[CH:8]=[CH:7][CH:6]=[CH:5][C:4]=1[C:9]1[CH:14]=[CH:13][C:12]([CH2:15][N:16]2[C:20]([C:21]([OH:23])=[O:22])=[C:19]([C:24]([OH:27])([CH3:26])[CH3:25])[N:18]=[C:17]2[CH2:28][CH2:29][CH3:30])=[CH:11][CH:10]=1)#[N:2].[N-:31]=[N+:32]=[N-:33].[Na+].Cl.C(N(CC)CC)C>C1(C)C=CC=CC=1>[OH:27][C:24]([C:19]1[N:18]=[C:17]([CH2:28][CH2:29][CH3:30])[N:16]([CH2:15][C:12]2[CH:11]=[CH:10][C:9]([C:4]3[CH:5]=[CH:6][CH:7]=[CH:8][C:3]=3[C:1]3[NH:33][N:32]=[N:31][N:2]=3)=[CH:14][CH:13]=2)[C:20]=1[C:21]([OH:23])=[O:22])([CH3:25])[CH3:26]

参与物

实验过程

Into the same device as used in Example 34 were placed 43.5 g (0.10 mole) of ethyl ester of 1-(2'-cyanobiphenyl-4-yl)methyl-4-(1-hydroxy-1-methylethyl)-2-propylimidazole-5-carboxylic acid, 8.5 g (0.13 mole) of sodium azide, 20.8 g (0.15 mole) of triethylamine hydrochloride and 206 ml of toluene. The mixture was reacted and treated in the same manner as in Example 34, giving 20.3 g(0.045 mole) of 4-(1-hydroxy-1-methylethyl)-2-propyl-1-{4-[2-(tetrazole-5-yl)phenyl]phenyl}methylimidazole-5-carboxylic acid (yield 45.0% based on ethyl ester of 1-(2'-cyanobiphenyl-4-yl)methyl-4-(1-hydroxy-1-methylethyl)-2-propylimidazole-5-carboxylic acid).