碘化氢 → 4-Iodo-6-(4-ethoxyphenyl)pyrimidine
反应方程式
F[C:2]1[CH:3]=[C:4](B(O)O)[CH:5]=[CH:6][C:7]=1[O:8][CH2:9][CH3:10].Cl[C:15]1[CH:20]=[C:19](Cl)[N:18]=[CH:17][N:16]=1.[IH:22]>>[I:22][C:15]1[CH:20]=[C:19]([C:4]2[CH:5]=[CH:6][C:7]([O:8][CH2:9][CH3:10])=[CH:2][CH:3]=2)[N:18]=[CH:17][N:16]=1参与物
4
实验过程
The compound was prepared according to Example 1 using 3-fluoro-4-ethoxyphenylboronic acid and 4,6-dichloropyrimidine. The resultant chloro compound was converted to iodo with hydroiodic acid as described in the general procedure.
后处理
- customThe compound was prepared
来源与证据
- ORD记录
- ord-06a354a8cc4c4b6b8452ec38e1ce6158
- 来源数据集
- uspto-grants-2015_10
- 专利号
- US09162987B2
反应笔记
加载中…