[F:1][C:2]1[CH:3]=[C:4]([C:10]2[CH:15]=[CH:14][CH:13]=[CH:12][CH:11]=2)[CH:5]=[CH:6][C:7]=1[O:8][CH3:9].[C:16](Cl)(=[O:18])[CH3:17].[Cl-].[Al+3].[Cl-].[Cl-].Cl>C(=S)=S.O>[F:1][C:2]1[CH:3]=[C:4]([C:10]2[CH:11]=[CH:12][C:13]([C:16](=[O:18])[CH3:17])=[CH:14][CH:15]=2)[CH:5]=[CH:6][C:7]=1[O:8][CH3:9]
Three grams of said 3-fluoro-4-methoxybiphenyl was dissolved in 14 ml of carbon disulfide, and 1.17 g of acetyl chloride and 2.36 g of aluminum chloride were added, followed by stirring the mixture for 10 hours. Twenty milliliters of 10% hydrochloric acid and then 5 ml of water were added, and the precipitate was filtered and washed with water. The resulting crude crystals were recrystallized from ethanol to obtain 2.75 g of 3'-fluoro-4'-methoxy-4-acetylbiphenyl (yield 76%).
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