2,4-噻唑烷二酮 → HCID 22494058，化合物

反应方程式

[CH3:1][O:2][C:3]1[CH:10]=[CH:9][C:6]([CH:7]=O)=[CH:5][C:4]=1[CH2:11][CH2:12][O:13][C:14]1[CH:19]=[CH:18][C:17]([C:20]([F:23])([F:22])[F:21])=[CH:16][CH:15]=1.[S:24]1[CH2:28][C:27](=[O:29])[NH:26][C:25]1=[O:30]>>[CH3:1][O:2][C:3]1[CH:10]=[CH:9][C:6]([CH2:7][CH:28]2[S:24][C:25](=[O:30])[NH:26][C:27]2=[O:29])=[CH:5][C:4]=1[CH2:11][CH2:12][O:13][C:14]1[CH:19]=[CH:18][C:17]([C:20]([F:23])([F:22])[F:21])=[CH:16][CH:15]=1

参与物

反应物 2

HCID 54372,4-噻唑烷二酮

HCID 22494083HCID 22494083，化合物

产物 1

HCID 22494058HCID 22494058，化合物

实验过程

Using 4-methoxy-3-{2-[4-(trifluoromethyl)phenoxy]ethyl}benzaldehyde and 2,4-thiazolidine dione, 5-(4-methoxy-3-2-[4-(trifluoromethyl)phenoxy]ethylbenzyl)-1,3-thiazolane-2,4-dione was obtained in the same method as in Production Example 27c) and then in Example 29).

来源与证据

ORD记录: ord-c4175b0f5e2f4c12b4c407223d7f1d1e
来源数据集: uspto-grants-2005_04
DOI: 10.6084/m9.figshare.5104873.v1
专利号: US06884821B1

反应笔记

加载中…