甲酰胺 → 甲酰胺

HRID 53363

反应方程式

HRID 53363 反应方程式
[C:1]([CH2:4][CH:5]([CH3:10])[C:6]([O:8][CH3:9])=[O:7])(=[O:3])[NH2:2].[CH:11](N)=[O:12].C[O-].[Na+].S(=O)(=O)(O)O>>[CH3:10][CH:5]([CH2:4][C:1]([O:12][CH3:11])=[O:3])[C:6]([O:8][CH3:9])=[O:7].[CH:1]([NH2:2])=[O:3]

参与物

6

反应物 4

HCID 713甲酰胺HCID 1118四氧化硫HCID 10942334甲醇钠HCID 11768702Methyl 3-carbamoylisobutyrate

产物 2

HCID 713甲酰胺HCID 15350甲基丁二酸二甲酯

实验过程

A one L stainless steel-made autoclave equipped with a stirrer was charged with 72.5 g of the methyl 3-carbamoylisobutyrate which had been obtained in the preceding item (2), 180 g of methyl formate, 96 g of methanol and 1.1 g of sodium methylate to proceed with heating reaction at 60° C. for 2 hours. The reaction product was cooled and then analyzed. As a result, the conversion of the methyl 3-carbamoylisobutyrate was 83.2% and, there were obtained dimethyl methylsuccinate at a selectivity of 99.8% based on the reacted methyl 3-carbamoylisobutyrate, and formamide at a selectivity of 98.4% based on the same. The sodium methylate in the reaction liquid was neutralized with sulfuric acid, and subsequently the reaction liquid was distilled by a conventional method. As a result, methyl formate and methanol were recovered and there were obtained 60 g of dimethyl methylsuccinate with at least 99% purity and 16 g of formamide with 99% purity. The recovery of these substances inclusive of an intermediate fraction was quantitative, respectively.

后处理

  1. customsubsequently the reaction liquid
  2. distillationwas distilled by a conventional method
  3. customAs a result, methyl formate and methanol were recovered

来源与证据

ORD记录
ord-f419fd2893ef45fb8f0259106ff5352c
来源数据集
uspto-grants-1997_04
专利号
US05618953

关联笔记

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