乙酰氯 → HCID 178419033，化合物

HRID 7525

反应方程式

HRID 7525 反应方程式
[NH2:1][C:2]1[N:7]=[CH:6][CH:5]=[CH:4][N:3]=1.[CH:8]1([N+:14]#[C-:15])[CH2:13][CH2:12][CH2:11][CH2:10][CH2:9]1.[N:16]1[CH:21]=[CH:20][CH:19]=[CH:18][C:17]=1[CH:22]=O.[C:24]([Cl:27])(=[O:26])[CH3:25]>Cl(O)(=O)(=O)=O>[Cl-:27].[C:24]([N+:1]1[C:22]([C:17]2[CH:18]=[CH:19][CH:20]=[CH:21][N:16]=2)=[C:15]([NH:14][CH:8]2[CH2:13][CH2:12][CH2:11][CH2:10][CH2:9]2)[N:3]2[CH:4]=[CH:5][CH:6]=[N:7][C:2]=12)(=[O:26])[CH3:25]

参与物

6

反应物 4

HCID 6367乙酰氯HCID 79782-氨基嘧啶HCID 14273吡啶-2-甲醛HCID 79129异氰环已烷

产物 1

HCID 178419033HCID 178419033，化合物

试剂、催化剂与溶剂 1

HCID 24247高氯酸溶剂

实验过程

Example 19 was carried out in accordance with the general directions for synthesis in process step a) from 1.0 ml (0.1 mmol) 2-amino-pyrimidine (0.1 M, DCM), 0.575 ml (0.115 mmol) cyclohexylisonitrile solution (0.2 M, DCM), 0.500 ml (0.15 mmol) pyridine-2-carbaldehyde solution (0.3 M, DCM) and 10 μl perchloric acid (w=20%) and in process step c) and d) by reacting the resultant reaction product with 0.4 mmol acetylchloride.

来源与证据

ORD记录
ord-1cc3531c804049d985d00a34b502b64b
来源数据集
uspto-grants-2006_08
专利号
US07087607B2

关联笔记

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