Bromobenzene → 9,9''-Diphenyl-9H,9'H,9''H-3,3':6',3''-tercarbazole

Reaktionsgleichung

[C:1]1([N:7]2[C:19]3[CH:18]=[CH:17][C:16](B4OC(C)(C)C(C)(C)O4)=[CH:15][C:14]=3[C:13]3[C:8]2=[CH:9][CH:10]=[CH:11][CH:12]=3)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.Br[C:30]1[CH:31]=[CH:32][C:33]2[NH:34][C:35]3[C:40]([C:41]=2[CH:42]=1)=[CH:39][C:38](Br)=[CH:37][CH:36]=3.C([O-])([O-])=O.[K+].[K+].Br[C:51]1[CH:56]=[CH:55][CH:54]=[CH:53][CH:52]=1>C1(C)C=CC=CC=1.O.CCO.C1C=CC([P]([Pd]([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)[P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)=CC=1>[C:51]1([N:34]2[C:35]3[CH:36]=[CH:37][C:38]([C:11]4[CH:10]=[CH:9][C:8]5[NH:7][C:19]6[C:14]([C:13]=5[CH:12]=4)=[CH:15][C:16]([C:4]4[CH:3]=[CH:2][C:1]5[N:7]([C:19]7[CH:14]=[CH:15][CH:16]=[CH:17][CH:18]=7)[C:8]7[C:13]([C:6]=5[CH:5]=4)=[CH:12][CH:11]=[CH:10][CH:9]=7)=[CH:17][CH:18]=6)=[CH:39][C:40]=3[C:41]3[C:33]2=[CH:32][CH:31]=[CH:30][CH:42]=3)[CH:56]=[CH:55][CH:54]=[CH:53][CH:52]=1